Integrand size = 16, antiderivative size = 93 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=-\frac {15}{4} a b \sqrt {x} \sqrt {a-b x}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {15}{4} a^2 \sqrt {b} \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.312, Rules used = {49, 52, 65, 223, 209} \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=-\frac {15}{4} a^2 \sqrt {b} \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right )-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {15}{4} a b \sqrt {x} \sqrt {a-b x} \]
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Rule 49
Rule 52
Rule 65
Rule 209
Rule 223
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-(5 b) \int \frac {(a-b x)^{3/2}}{\sqrt {x}} \, dx \\ & = -\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {1}{4} (15 a b) \int \frac {\sqrt {a-b x}}{\sqrt {x}} \, dx \\ & = -\frac {15}{4} a b \sqrt {x} \sqrt {a-b x}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {1}{8} \left (15 a^2 b\right ) \int \frac {1}{\sqrt {x} \sqrt {a-b x}} \, dx \\ & = -\frac {15}{4} a b \sqrt {x} \sqrt {a-b x}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {1}{4} \left (15 a^2 b\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-b x^2}} \, dx,x,\sqrt {x}\right ) \\ & = -\frac {15}{4} a b \sqrt {x} \sqrt {a-b x}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {1}{4} \left (15 a^2 b\right ) \text {Subst}\left (\int \frac {1}{1+b x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {a-b x}}\right ) \\ & = -\frac {15}{4} a b \sqrt {x} \sqrt {a-b x}-\frac {5}{2} b \sqrt {x} (a-b x)^{3/2}-\frac {2 (a-b x)^{5/2}}{\sqrt {x}}-\frac {15}{4} a^2 \sqrt {b} \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a-b x}}\right ) \\ \end{align*}
Time = 0.23 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.89 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=\frac {\sqrt {a-b x} \left (-8 a^2-9 a b x+2 b^2 x^2\right )}{4 \sqrt {x}}-\frac {15}{2} a^2 \sqrt {b} \arctan \left (\frac {\sqrt {b} \sqrt {x}}{-\sqrt {a}+\sqrt {a-b x}}\right ) \]
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Time = 0.09 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.95
method | result | size |
risch | \(-\frac {\sqrt {-b x +a}\, \left (-2 b^{2} x^{2}+9 a b x +8 a^{2}\right )}{4 \sqrt {x}}-\frac {15 a^{2} \sqrt {b}\, \arctan \left (\frac {\sqrt {b}\, \left (x -\frac {a}{2 b}\right )}{\sqrt {-b \,x^{2}+a x}}\right ) \sqrt {x \left (-b x +a \right )}}{8 \sqrt {x}\, \sqrt {-b x +a}}\) | \(88\) |
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Time = 0.24 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.47 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=\left [\frac {15 \, a^{2} \sqrt {-b} x \log \left (-2 \, b x + 2 \, \sqrt {-b x + a} \sqrt {-b} \sqrt {x} + a\right ) + 2 \, {\left (2 \, b^{2} x^{2} - 9 \, a b x - 8 \, a^{2}\right )} \sqrt {-b x + a} \sqrt {x}}{8 \, x}, \frac {15 \, a^{2} \sqrt {b} x \arctan \left (\frac {\sqrt {-b x + a}}{\sqrt {b} \sqrt {x}}\right ) + {\left (2 \, b^{2} x^{2} - 9 \, a b x - 8 \, a^{2}\right )} \sqrt {-b x + a} \sqrt {x}}{4 \, x}\right ] \]
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Result contains complex when optimal does not.
Time = 5.09 (sec) , antiderivative size = 267, normalized size of antiderivative = 2.87 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=\begin {cases} \frac {2 i a^{\frac {5}{2}}}{\sqrt {x} \sqrt {-1 + \frac {b x}{a}}} + \frac {i a^{\frac {3}{2}} b \sqrt {x}}{4 \sqrt {-1 + \frac {b x}{a}}} - \frac {11 i \sqrt {a} b^{2} x^{\frac {3}{2}}}{4 \sqrt {-1 + \frac {b x}{a}}} + \frac {15 i a^{2} \sqrt {b} \operatorname {acosh}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{4} + \frac {i b^{3} x^{\frac {5}{2}}}{2 \sqrt {a} \sqrt {-1 + \frac {b x}{a}}} & \text {for}\: \left |{\frac {b x}{a}}\right | > 1 \\- \frac {2 a^{\frac {5}{2}}}{\sqrt {x} \sqrt {1 - \frac {b x}{a}}} - \frac {a^{\frac {3}{2}} b \sqrt {x}}{4 \sqrt {1 - \frac {b x}{a}}} + \frac {11 \sqrt {a} b^{2} x^{\frac {3}{2}}}{4 \sqrt {1 - \frac {b x}{a}}} - \frac {15 a^{2} \sqrt {b} \operatorname {asin}{\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}} \right )}}{4} - \frac {b^{3} x^{\frac {5}{2}}}{2 \sqrt {a} \sqrt {1 - \frac {b x}{a}}} & \text {otherwise} \end {cases} \]
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Time = 0.29 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.20 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=\frac {15}{4} \, a^{2} \sqrt {b} \arctan \left (\frac {\sqrt {-b x + a}}{\sqrt {b} \sqrt {x}}\right ) - \frac {2 \, \sqrt {-b x + a} a^{2}}{\sqrt {x}} - \frac {\frac {7 \, \sqrt {-b x + a} a^{2} b^{2}}{\sqrt {x}} + \frac {9 \, {\left (-b x + a\right )}^{\frac {3}{2}} a^{2} b}{x^{\frac {3}{2}}}}{4 \, {\left (b^{2} - \frac {2 \, {\left (b x - a\right )} b}{x} + \frac {{\left (b x - a\right )}^{2}}{x^{2}}\right )}} \]
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Time = 76.10 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.08 \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=-\frac {{\left (\frac {15 \, a^{2} \log \left ({\left | -\sqrt {-b x + a} \sqrt {-b} + \sqrt {{\left (b x - a\right )} b + a b} \right |}\right )}{\sqrt {-b}} - \frac {{\left ({\left (2 \, b x - 7 \, a\right )} {\left (b x - a\right )} - 15 \, a^{2}\right )} \sqrt {-b x + a}}{\sqrt {{\left (b x - a\right )} b + a b}}\right )} b^{2}}{4 \, {\left | b \right |}} \]
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Timed out. \[ \int \frac {(a-b x)^{5/2}}{x^{3/2}} \, dx=\int \frac {{\left (a-b\,x\right )}^{5/2}}{x^{3/2}} \,d x \]
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